 X 1.8 = 116.64 32.4 155.52 97.2 x*-8- 272.16 272.16*97.2 = 2. 80 feet, which is the distance of the center of gravity of the trapezoid from the rear face of the wall. The pressure of the earth on the rear wall, as stated above, is very uncertain; a value...  General Design of Warships - Page 88de William Hovgaard - 1920 - 306 pagesAffichage du livre entier - À propos de ce livre
 | William Cain - 1879 - 216 pages
...just to right of joint to which it refers = width X mean height X IF. In this case IF=JI=0.94. I is the distance of the center of gravity of the trapezoid from the crown, and m the corresponding moment. V is the volume from the crown to the joint to which it refers... | |
 | 1879 - 550 pages
...lying just to right of joint to which it refers = width X mean height XlF. In this case IF=JI=0.94 I is the distance of the center of gravity of the trapezoid from the crown, and m the corresponding moment. V is the volume from the crown to the joint to which it refers... | |
 | American School of Correspondence - 1908 - 556 pages
...then found numerically as follows: 64.8 X 1.8=116.64 97.2 272.16 272.16-97.2 = 2. 80 feet, which is the distance of the center of gravity of the trapezoid from the rear face of the wall. The pressure of the earth on the rear wall, as stated above, is very uncertain;... | |
 | 1909 - 560 pages
...numerically as follows : 64.8 X 1.8 = 116.64 32.4 155.52 97.2 * 272.16 272.16 -^97.2 = 2. 80 feet, which is the distance of the center of gravity of the trapezoid from the rear face of the wall. The pressure of the earth on the rear wall, as stated above, is very uncertain;... | |
 | Leonard Church Urquhart - 1915 - 48 pages
...19.33 square feet. The upward pressure of the soil on this area is 19.33 x 4°°° = 77300 pounds. The distance of the center of gravity of the trapezoid from the edge of the column (ab) is i BAN OS ('PIPE SLEEVES-I—I PLATES 3'!i3'«f N ' — - I — — ^r —... | |
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